Welcome to Card Game DB
Register now to gain access to all of our features. Once registered and logged in, you will be able to create topics, post replies to existing threads, give reputation to your fellow members, get your own private messenger, post status updates, manage your profile and so much more. If you already have an account, login here - otherwise create an account for free today!
Register now to gain access to all of our features. Once registered and logged in, you will be able to create topics, post replies to existing threads, give reputation to your fellow members, get your own private messenger, post status updates, manage your profile and so much more. If you already have an account, login here - otherwise create an account for free today!
Sweet Donnel Hill
Submitted
Guest
, -- | Last updated --
![]() |
|
Want to build a deck using this card? Check out the A Game of Thrones 2nd Edition Deck Builder! |
Recent Decks Using This Card:
10 Comments
Yep. Donnel doesn't say "printed", so you lose all keywords, both printed and gained, and even if you have multiple instances of the same keyword. Literally ALL keywords.
It's worth noting that not only is this the way "loses/gains all keywords" is handled in Conquest, it is also the way "loses/gains all keywords" was handled in AGoT 1.0.
The terminology "loses/gains all instances of <whatever keyword>" is what would be used if the single loses/gains effect is to "overpower" all other modifying effects. Otherwise, "all keywords" refers to a single instance of each keyword that exists in the game - not all instances necessary to ensure that the card will never/always have a functioning keyword.
Of course, FFG could rule differently for AGoT 2.0, but they have been pretty consistent about this across most games.
But I cannot find that conversation in any logs. I guess I'll have to ask Nate again.
ktom is right, I was wrong (memory glitch i guess =_= )
“All keywords†means “one instance of each keywordâ€.
If a character bypass one of mine using stealth, and then I defend with Sweet Donnel Hill, can I also defend with my bypassed character?
No. Two reasons:
1. If the attacking character loses stealth, it does not retroactively "un-bypass" the defending character. Once a character is bypassed by stealth, it cannot be declared as a defender in that challenge, period. The attacker does not need to keep stealth (or remain in play, etc.) in order for stealth to keep working.
2. All defenders are declared at the same time. So even if #1 was not true, defending with SDH wouldn't help because by the time he is declared as a defender (so that the attacking characters lose their keywords), it would be too late to declare additional defenders, "retroactively un-bypassed" or not.
"the name of the keyword stealth is misleading, it should be called "deceive" or "distraction""
~mplain
cannot agree more